Tugas Jaringan Komputer Pertemuan 2

Hitunglah jumlah Network dan Host yang akanterbentuk dari alamat IP Address dibawah ini, kemudian buat rincian alamat (Network, Broadcast) beserta alamat yang dapat diberikan kepada setiap host (minimal untuk 5 host/komputer):

1. 192.168.10.1/30

2. 172.168.10.1/16

3. 172.168.10.0/22

4. 10.168.5.1/8

5. 10.168.5.1/17

Jawaban :

1. 192.168.10.1/30

Netmask = 255.255.255.252

Subnet    = 11111111.11111111.11111111.11111100 : /30

Network = 2n = 26 = 64 network

Host       = 2h-2 = 22-2 = 2 host

Alokasi IP 

Network   : 192.168.10.0

Host         : 192.168.10.1 - 192.168.10.2

Broadcast : 192.168.10.3

2. 172.168.10.1/16

Netmask = 255.255.000.000

Subnet    = 11111111.11111111.00000000.00000000 : /16

Network = 2n = 20 = 1 network

Host       = 2h-2 = 216-2 = 65.534 host

Alokasi IP 

Network   :172.168.0.0

Host         : 172.168.0.1 - 192.168.255.254

Broadcast : 192.168.255.255

3. 172.168.10.0/22

Netmask = 255.255.252.000

Subnet    = 11111111.11111111.11111100.00000000 : /22

Network = 2n = 26 = 64 network

Host       = 2h-2 = 210-2 = 1.022 host

Alokasi IP 

Network   :172.168.10.0

Host         : 172.168.10.1 - 192.168.255.254

Broadcast : 192.168.255.255

4. 10.168.5.1/8

Netmask = 255.000.000.000

Subnet    = 11111111.00000000.00000000.00000000 : /8

Network = 2n = 20 = 1 network

Host       = 2h-2 = 224-2 = 167.772.614 host

Alokasi IP 

Network   :10.168.5.0

Host         : 10.0.0.1 - 10.255.255.254

Broadcast : 10.255.255.255

5. 10.168.5.1/17

Netmask = 255.255.128.000

Subnet    = 11111111.11111111.10000000.00000000 : /17

Network = 2n = 21 = 2 network

Host       = 2h-2 = 215-2 = 32.766 host

Alokasi IP 

Network   :10.168.0.0

Host         : 10.168.0.1 - 10.168.127.254

Broadcast : 10.168.127.255